; ======================================================================
; Calculate and append CRC
;
; The CRC is calculated 4 bits at a time, using a precomputed table of
; 16 values. Each value is 16 bits, but only the 8 significant bits are
; stored. The table should not cross a 256-byte page. The check.py script
; will check for this.
;
; A bitwise algorithm would be a little smaller, but takes more time.
; In fact, it takes too much time for the USB controller in my laptop.
; The poll frequently is so high, that a lot of time is spent in the
; interrupt handler, sending NAK packets, leaving little time for the
; actual checksum calculation. An 8 bit algoritm would be even faster,
; but requires a lookup table of 512 bytes.
;
; Copyright (C) 2006 Dick Streefland
;
; This is free software, licensed under the terms of the GNU General
; Public License as published by the Free Software Foundation.
; ======================================================================
#include "def.h"
; ----------------------------------------------------------------------
; void crc(unsigned char *data, unsigned char len);
; ----------------------------------------------------------------------
#define data r24
#define len r22
#define b r18
#define tmp r19
#define zl r20
#define crc_l r24
#define crc_h r25
.text
.global crc
.type crc, @function
crc:
; crc = 0xffff
movw XL, r24
ldi crc_h, 0xff
ldi crc_l, 0xff
lsl len
breq done
ldi zl, lo8(crc4tab)
ldi ZH, hi8(crc4tab)
next_nibble:
; b = (len & 1 ? b >> 4 : *data++)
swap b
sbrs len, 0
ld b, X+
; index = (crc ^ b) & 0x0f
mov ZL, crc_l
eor ZL, b
andi ZL, 0x0f
; crc >>= 4
swap crc_h
swap crc_l
andi crc_l, 0x0f
mov tmp, crc_h
andi tmp, 0xf0
or crc_l, tmp
andi crc_h, 0x0f
; crc ^= crc4tab[index]
add ZL, zl
lpm tmp, Z+
eor crc_h, tmp
andi tmp, 1
eor crc_h, tmp
eor crc_l, tmp
; next nibble
dec len
brne next_nibble
done:
; crc ^= 0xffff
com crc_l
com crc_h
; append crc to buffer
st X+, crc_l
st X+, crc_h
ret
; ----------------------------------------------------------------------
; CRC table. As bits 1..8 are always zero, omit them.
; ----------------------------------------------------------------------
.section .progmem.crc,"a",@progbits
;;; .align 4 ; avoid crossing a page boundary
crc4tab:
.byte 0x00+0x00
.byte 0xcc+0x01
.byte 0xd8+0x01
.byte 0x14+0x00
.byte 0xf0+0x01
.byte 0x3c+0x00
.byte 0x28+0x00
.byte 0xe4+0x01
.byte 0xa0+0x01
.byte 0x6c+0x00
.byte 0x78+0x00
.byte 0xb4+0x01
.byte 0x50+0x00
.byte 0x9c+0x01
.byte 0x88+0x01
.byte 0x44+0x00
/* ---------------------------------------------------------------------- *\
#!/usr/bin/python
for crc in range(16):
for bit in range(4):
xor = crc & 1
crc >>= 1
if xor:
crc ^= 0xA001 # X^16 + X^15 + X^2 + 1 (reversed)
print "\t.byte\t0x%02x+0x%02x" % (crc >> 8, crc & 0xff)
\* ---------------------------------------------------------------------- */